A Train After Travelling 150 Km Meets With An Accident . After travelling for 3 0 minutes a train meets with an accident, due to which it has to stop for 4 5 minutes. The delay in arrival is the time difference between the time the train takes to cover the rest distance $ y $ after the accident and time it would have taken without the.
Conceptual Marketing Corporation ANALYSIS INFORMATION from www.petrofilm.com
A train after traveling 150 km meets with an accident and then proceeds with 3/5 of its former speed and arrives its destination 8 hours late. (or original time is $45×4=180$ minutes $=3$ hour). Had the accident occurred 360 km further, it would have reached the destination 4 hours.
Conceptual Marketing Corporation ANALYSIS INFORMATION
So the speed of the train after the accident is $ \dfrac{3}{4}x $ km/hr. A) 36 kmph b) 48 kmph c) 54 kmph d) 58 kmph Had the accident occurred 24 km further, it would have reached the destination only 25. Had the accident occurred 30 kms further, the train would have been late by only 21 minutes.
Source: venturebeat.com
A train 300 m long is running at a speed of 54 km/hr. After travelling for 3 0 minutes a train meets with an accident, due to which it has to stop for 4 5 minutes. Had the accident occurred 30 kms further, the train would have been late by only 21 minutes. A train after travelling 50 km meets.
Source: wheelchairtravel.org
Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. #revoclasses #shorttrickmaths #aptitudea train meets with an accident after travelling 30 kms, after which it moves with 4/5 th of its original speed and a. Had the accident.
Source: www.cbsnews.com
#timeanddistancebyprabhakarsir #careeradhyapana train after travelling 225 km meets with an accident and then proceeds at 4/7 of its former speed and arrives. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Total distance which needs to be covered = (300+150)m = 450m. After travelling for 3 0 minutes a train meets with an.
Source: lrt.daxack.ca
(a) 960 km (b) 870 km (c) 840 km (d) 1100 km A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. I.e., after travelling $100$ km, train takes $3$ hour for its journey and therefore covers a distance of $3×50=150$ km. After.
Source: venturebeat.com
Had the accident occurred 6 0 km later, the train would have reached 3 0 minutes earlier. Due to the accident its speed is also reduced to 3 2 of its former value and the train reaches its destination 1 hour 3 0 minutes late. After this the train moves at 75% speed of its original speed and reaches to.
Source: suomiweed.com
#timeanddistancebyprabhakarsir #careeradhyapana train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives. A train 300 m long is running at a speed of 54 km/hr. #revoclasses #shorttrickmaths #aptitudea train meets with an accident after travelling 30 kms, after which it moves with 4/5 th of its original speed and a..
Source: caymaneco.org
Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Therefore distance between a and b $=100+150=250$ km. Let y be the balance distance to be covered and x be the former speed. A train after traveling 150 km meets with an accident and then proceeds with 3/5 of its former speed and arrives.
Source: www.petrofilm.com
Let us assume the distance the train has to cover after the accident as $ y $ km and the speed of the train before the accident is $ x $ km/hr. The delay in arrival is the time difference between the time the train takes to cover the rest distance $ y $ after the accident and time it.
Source: www.firstpost.com
The length of journey is Then time taken will be. A train after travelling 50 km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. Thus, extra time = 2 hour. Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours.
Source: railcolornews.com
Due to the accident its speed is also reduced to 3 2 of its former value and the train reaches its destination 1 hour 3 0 minutes late. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. A train after travelling 50 km meets with an accident and then proceeds at 3/4 of.
Source: mas.txt-nifty.com
Then time taken will be. It means it covers 300 km distance in 5 hours. Total distance which needs to be covered = (300+150)m = 450m. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Speed = {54 × (5/18)} m/sec = 15 m/sec.
Source: www.cbs.com
It means it covers 300 km distance in 5 hours. After this the train moves at 75% speed of its original speed and reaches to destination 4 hours late. Let us assume the distance the train has to cover after the accident as $ y $ km and the speed of the train before the accident is $ x $.
Source: www.rediff.com
Speed = {54 × (5/18)} m/sec = 15 m/sec. What is the distance travelled by the train? #revoclasses #shorttrickmaths #aptitudea train meets with an accident after travelling 30 kms, after which it moves with 4/5 th of its original speed and a. A train after travelling 50 km meets with an accident and then proceeds at 3/4 of its former.
Source: news.sky.com
After this the train moves at 75% speed of its original speed and reaches to destination 4 hours late. What is the total distance travelled by the train ? Then time taken will be. Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours. Required time = 450 / 15 = 30 seconds
Source: montgomerycountypolicereporter.com
A train 300 m long is running at a speed of 54 km/hr. What is the distance travelled by the train? If the accident would occur at 150 km ahead in the same line then the train reaches only 3.5 hours late. A train after traveling 150 km meets with an accident and then proceeds with 3/5 of its former.
Source: www.ibtimes.co.in
The length of journey is Had the accident occurred 360 km further, it would have reached the destination 4 hours. (or original time is $45×4=180$ minutes $=3$ hour). #revoclasses #shorttrickmaths #aptitudea train meets with an accident after travelling 30 kms, after which it moves with 4/5 th of its original speed and a. A train 300 m long is running.
Source: www.petrofilm.com
The length of journey is So the speed of the train after the accident is $ \dfrac{3}{4}x $ km/hr. A train after travelling 50kms meets with an accident and then proceeds at 3/4th of its former speed and arrives at its destination 35 minutes late. Therefore distance between a and b $=100+150=250$ km. Had the accident occurred 6 0 km.
Source: www.petrofilm.com
Then time taken will be. Had the accident occurred 6 0 km later, the train would have reached 3 0 minutes earlier. A train after travelling 50 km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. Had the accident occurred 6 0 km later, the train would.
Source: caymaneco.org
Due to the accident its speed is also reduced to 3 2 of its former value and the train reaches its destination 1 hour 3 0 minutes late. #timeanddistancebyprabhakarsir #careeradhyapana train after travelling 225 km meets with an accident and then proceeds at 4/7 of its former speed and arrives. What is the total distance traveled by the train?: A).
Source: suomiweed.com
A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. If the accident would occur at 150 km ahead in the same line then the train reaches only 3.5 hours late. The length of journey is So the speed of the train after.
